I like an eyemask too, although I tend to only use it if I wake up too early and want to go back to sleep - it’s too hot to keep it on all night.

I’m the same - as soon as I’m on the phone I want to be on my feet, even though generally I’m happy to be sat.

Mushroom cloud

deleted by creator

It’s too easy to quit though; I can never get going.

It’s more like let’s get some good but utterly unimportant stuff done

Everyone in this thread should finish with lol

That was my 1st, 2nd + 3rd question

I think as long as it gets some responses it’s being useful.

Swimming is the easiest for me to do - I find the rhythm soothing and I like being away from any technology so I can just think or focus on the swimming.

I’ve just counted and I have 74 Firefox windows open… god knows how many tabs that is…

Wow, flawless. Love it.

The Greeks were also famous for making multiple, multiple handwritten copies of any literature they encountered

You kinda had to then, since archival paper wasn’t invented and papyrus doesn’t normally last very long.

Checking in! Thanks for your work, this seems to be about the most stable instance across the whole of Lemmy.

I like the idea of the Scaled view; some of those smaller communities don’t ever show up unless I view by New.

I only know because you just told me. What’s a bonzi anyway?

That’s my plan when Win10 gets too old. I’ve run Linux before (although not as my daily driver) so the only thing worrying me is choosing which distro…

I’ve been using AI summarisation for things like this so I don’t need to read and I can satisfy my curiosity (normally what film they’re talking about). Normally it’s not worth the effort but it’s quicker than reading the article myself.

Yeah, it’s pretty bad:

Six days later and there’s 44 75 on the first page (top 20 Active), so I guess OP was correct about human nature.

This took longer than just adding them up, but that’s not the point:

Array.from(document.querySelectorAll('[aria-label="Downvote"] span.ms-2'))
    .reduce((acc, e) => acc + parseInt(e.innerText, 10) || 0, 0)